Optimal. Leaf size=50 \[ \frac{\left (\frac{b^2}{4 c}+b x+c x^2\right )^n \left (\frac{b e}{2 c}+e x\right )^{m+1}}{e (m+2 n+1)} \]
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Rubi [A] time = 0.054894, antiderivative size = 50, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.054 \[ \frac{\left (\frac{b^2}{4 c}+b x+c x^2\right )^n \left (\frac{b e}{2 c}+e x\right )^{m+1}}{e (m+2 n+1)} \]
Antiderivative was successfully verified.
[In] Int[((b*e)/(2*c) + e*x)^m*(b^2/(4*c) + b*x + c*x^2)^n,x]
[Out]
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Rubi in Sympy [A] time = 16.2715, size = 37, normalized size = 0.74 \[ \frac{\left (\frac{b e}{2 c} + e x\right )^{m + 1} \left (\frac{b^{2}}{4 c} + b x + c x^{2}\right )^{n}}{e \left (m + 2 n + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((1/2*b*e/c+e*x)**m*(1/4/c*b**2+b*x+c*x**2)**n,x)
[Out]
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Mathematica [A] time = 0.0448261, size = 54, normalized size = 1.08 \[ \frac{2^{-2 n-1} (b+2 c x) \left (\frac{(b+2 c x)^2}{c}\right )^n \left (\frac{b e}{2 c}+e x\right )^m}{c (m+2 n+1)} \]
Antiderivative was successfully verified.
[In] Integrate[((b*e)/(2*c) + e*x)^m*(b^2/(4*c) + b*x + c*x^2)^n,x]
[Out]
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Maple [A] time = 0.005, size = 58, normalized size = 1.2 \[{\frac{2\,cx+b}{2\,c \left ( 1+m+2\,n \right ) } \left ({\frac{e \left ( 2\,cx+b \right ) }{2\,c}} \right ) ^{m} \left ({\frac{4\,{c}^{2}{x}^{2}+4\,bxc+{b}^{2}}{4\,c}} \right ) ^{n}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((1/2*b*e/c+e*x)^m*(1/4*b^2/c+b*x+c*x^2)^n,x)
[Out]
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Maxima [A] time = 0.77516, size = 107, normalized size = 2.14 \[ \frac{{\left (2 \, c e^{m} x + b e^{m}\right )} c^{-m - n - 1} e^{\left (m \log \left (2 \, c x + b\right ) + 2 \, n \log \left (2 \, c x + b\right )\right )}}{{\left (2^{2 \, n + 2} n + 2^{2 \, n + 1}\right )} 2^{m} + 2^{m + 2 \, n + 1} m} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + 1/4*b^2/c)^n*(e*x + 1/2*b*e/c)^m,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.225417, size = 85, normalized size = 1.7 \[ \frac{{\left (2 \, c x + b\right )} \left (\frac{2 \, c e x + b e}{2 \, c}\right )^{m} e^{\left (2 \, n \log \left (\frac{2 \, c e x + b e}{2 \, c}\right ) + n \log \left (\frac{c}{e^{2}}\right )\right )}}{2 \,{\left (c m + 2 \, c n + c\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + 1/4*b^2/c)^n*(e*x + 1/2*b*e/c)^m,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((1/2*b*e/c+e*x)**m*(1/4/c*b**2+b*x+c*x**2)**n,x)
[Out]
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GIAC/XCAS [A] time = 0.221909, size = 140, normalized size = 2.8 \[ \frac{2 \, c x e^{\left (-m{\rm ln}\left (2\right ) - 2 \, n{\rm ln}\left (2\right ) + m{\rm ln}\left (2 \, c x + b\right ) + 2 \, n{\rm ln}\left (2 \, c x + b\right ) - m{\rm ln}\left (c\right ) - n{\rm ln}\left (c\right ) + m\right )} + b e^{\left (-m{\rm ln}\left (2\right ) - 2 \, n{\rm ln}\left (2\right ) + m{\rm ln}\left (2 \, c x + b\right ) + 2 \, n{\rm ln}\left (2 \, c x + b\right ) - m{\rm ln}\left (c\right ) - n{\rm ln}\left (c\right ) + m\right )}}{2 \,{\left (c m + 2 \, c n + c\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + 1/4*b^2/c)^n*(e*x + 1/2*b*e/c)^m,x, algorithm="giac")
[Out]